SPM Mathematics Trial 2021 (Selangor), Paper 2 (Question 14)


Question 14:
(a) Given volume of gas, V varies inversely as the pressure, P. Given V = 2 m3 and P = 500 Nm-2, express V in terms of P. [2 marks]

(b) Based on the answer in 14(a), complete Table 3 in the answer space. [1 mark]

(c) For this part of the question, use the graph paper provided. You may use a flexible curve rule.
Based on your answers in 14(b) and using a scale of 2 cm to 100 Nm-2 on the x-axis and 2 cm to 1 m3 on the y-axis, draw the graph for 100 ≤ x ≤ 800. [4 marks]

(d) From the graph in 14(c), find the volume of gas, in m3, if the pressure of gas is 300 Nm-2. [1 mark]

Answer:
P100200250400500800
V105421.25
Table 3


Solution:
(a)

Vα 1 P V= k P k=VP k=( 2 )( 500 ) k=1000 V= 1000 P


(b)
V= 1000 P V= 1000 400 =2.5

P100200250400500800
V10542.521.25


(c), (d)


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