Question 4:
Diagram 2 in the answer space shows a rectangle door with the height of 2.5 m and the width of 1 m. The distance between P and Q is 1.2 m.
(a) On Diagram 2 in the answer space, mark the angle between the door and the wall. [1 mark]
(b) Hence, calculate the angle of opening of the door. [3 marks]
Answer:

Solution:
(b)

sinx=0.61 x=36o52‘angle of opening=x+x =36o52‘+36o52‘ =73o44‘
Diagram 2 in the answer space shows a rectangle door with the height of 2.5 m and the width of 1 m. The distance between P and Q is 1.2 m.
(a) On Diagram 2 in the answer space, mark the angle between the door and the wall. [1 mark]
(b) Hence, calculate the angle of opening of the door. [3 marks]
Answer:

Solution:
(b)

sinx=0.61 x=36o52‘angle of opening=x+x =36o52‘+36o52‘ =73o44‘
Question 5:
A furniture factory distributes plastic chairs and wooden chairs to supplier A and supplier B. Supplier A received 4 containers of plastic chairs and 3 containers of wooden chairs, with a total of 290 chairs. Supplier B received 5 containers of plastic chairs and 7 containers of wooden chairs, with a total of 460 chairs.
Using matrix method, find the number of plastic chairs and the number of wooden chairs in each containers. [5 marks]
Solution:
x = Number of plastic chairs in a container
y = Number of wooden chairs in a container
4x+3y=290 ………….. (1)5x+7y=460 …………… (2)(4 35 7)(xy)=(290460) (xy)=128−15(7 −3−5 4)(290460) (xy)=113((7)(290)+(−3)(460)(−5)(290)+(4)(460)) (xy)=113(2030−1380−1450+1840) (xy)=(5030)x=50 and y=30
A furniture factory distributes plastic chairs and wooden chairs to supplier A and supplier B. Supplier A received 4 containers of plastic chairs and 3 containers of wooden chairs, with a total of 290 chairs. Supplier B received 5 containers of plastic chairs and 7 containers of wooden chairs, with a total of 460 chairs.
Using matrix method, find the number of plastic chairs and the number of wooden chairs in each containers. [5 marks]
Solution:
x = Number of plastic chairs in a container
y = Number of wooden chairs in a container
4x+3y=290 ………….. (1)5x+7y=460 …………… (2)(4 35 7)(xy)=(290460) (xy)=128−15(7 −3−5 4)(290460) (xy)=113((7)(290)+(−3)(460)(−5)(290)+(4)(460)) (xy)=113(2030−1380−1450+1840) (xy)=(5030)x=50 and y=30
∴ Number of plastic chairs in a container = 50
Number of wooden chairs in a container = 30