SPM Mathematics 2017, Paper 2 (Questions 13 & 14)


Question 13 (12 marks):
(a) Diagram 7.1 shows K (5, 1) drawn on a Cartesian plane.
Diagram  7.1

Transformation T is a translation  ( 3  4 )
Transformation P is a reflection in the line y = 2.
State the coordinates of the images of point K under each of the following transformations:
(i) T2,
(ii) TP.


(b) Diagram 7.2 shows two pentagons KLMNP and QRSTU, drawn on a Cartesian plane.

Diagram  7.2

(i)
Pentagon QRSTU  is the image of pentagon KLMNP under the combined transformation WV.
Describe in full the transformation:
(a) V,
(b) W.

(ii)
 It is given that pentagon QRSTU represents a region with an area of 90 m2.
Calculate the area, in m2, of pentagon KLMNP.


Solution:
(a)



(i)
TT = K(5, 1) → T1 → K’(2, 5) ) → T2 → K’’(–1, 9)
(ii) TP =  K(5, 1) → P → K’(5, 3) → T → K’’(2, 7)


(b)


(b)(i)(a)

V: 90o rotation in clockwise direction at point K(3, 7).

(b)(i)(b)
W: Enlargement at point (1, 6) with scale factor 3.

(b)(ii)
Area of QRSTU = (scale factor)2 × area of object
Area of QRSTU = 32 × Area of KLMNP
90 m2 = 9 × Area of KLMNP
Area of KLMNP = 90/9 = 10 m2



Question 14 (12 marks):
The data in Diagram 8 shows the mass, in g, of 30 strawberries plucked by a tourist from a farm.

Diagram 8

(a)
Based on the Diagram 8, complete Table 3 in the answer space.

(b)
Based on Table 3, calculate the estimated mean mass of a strawberry.

(c)
For this part of the question, use graph paper.
By using the scale of 2 cm to 10 g on the horizontal axis and 2 cm to 1 strawberry on the vertical axis, draw a histogram for the data.

(d)
Based on the histogram drawn in 14(c), state the number of strawberries with the mass of more than 50 g.

Answer:




Solution:
(a)


(b)
Estimated mean mass = Total [ midpoint×frequency ] Total frequencies = 2( 14.5 )+5( 24.5 )+10( 34.5 )+8( 44.5 )+ 3( 54.5 )+2( 64.5 ) 2+5+10+8+3+2 = 1145 30 =38.17


(c)


(d)
Number of strawberries with the mass more than 50 g
= 3 + 2
= 5 



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