SPM Mathematics 2016, Paper 2 (Questions 1 & 2)

Question 1 (3 marks):
On the graph in the answer space, shade the region which satisfies all three inequalities y ≥ –3x + 6, y > x + 1 and y ≤ 5.

Answer:

Solution:

Question 2 (4 marks):
Solve the following quadratic equation:

- \frac{2}{3 x - 5} = \frac{x}{3 x - 1}

Solution:

\begin{array}{l} - \frac{2}{3 x - 5} = \frac{x}{3 x - 1} \\ - 2 (3 x - 1) = x (3 x - 5) \\ - 6 x + 2 = 3 x^{2} - 5 x \\ 3 x^{2} - 5 x + 6 x - 2 = 0 \\ 3 x^{2} + x - 2 = 0 \\ (3 x - 2) (x + 1) = 0 \\ 3 x - 2 = 0 or x + 1 = 0 \\ x = \frac{2}{3} or x = - 1 \end{array}

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