7.3.4 Graphs of Motion, SPM Paper 2 (Long Questions)


Question 9:
Diagram below shows the speed-time graph for the movement of an object for a period of 34 seconds.


(a) State the duration of time, in seconds, for which the object moves with uniform speed.
(b) Calculate the rate of change of speed, in ms-2, of the object for the first 8 seconds.
(c) Calculate the value of u, if the average of speed of the object for the last 26 seconds is 6 ms-1.

Solution:
(a) Duration of time = 26s – 20s = 6s

(b) Rate of change of speed for the first 8 seconds = 106 08 = 4 8 = 1 2  ms 2

(c) Speed= Distance Time ( 1 2 ×12×( 6+u ) )+( 6×u )+( 1 2 ×8×u ) 26 =6   36+6u+6u+4u=156    16u=120    u=7.5  ms 1




Question 10:
Diagram shows the speed-time graph for the movement of two particles, J and K, for a period of t s. The graph ABCD represents the movement of J and the graph AE represents the movement of K. Both particles start at the same point and move along the same route.



(a) State the uniform speed, in ms-1, of particle J.
(b) Calculate the rate of change of speed, in ms-2, of particle J for the first 13 s.
(c) At t s, the difference between the distance travelled by J and K is 169 m. Calculate the value of t.
[ 6 marks ]
Solution:
(a)
Uniform speed of particle J = 26 ms-1

(b)
Rate of change of speed of particle J for the first 13 s
= 26 0 13 0 = 2 m s 2


(c)
Given at t s, the difference between the distance travelled by J and K is 169
(distance travelled by particle J) – (distance travelled by particle K) = 169
[ ½ (t – 13 + t) × 26 ] – [ ½ (26) (t )] = 169
[ 13 (2t – 13) ] – 13t  = 169
( 26t – 169 – 13t ) = 169
13t  = 338
t  = 26
 

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