4.3 Operations on Statements

4.3 Operations on Statements
 
(A) Nagating a Statement using ‘No’ or ‘Not’
 
1. Negation of a statement refers to changing the truth value of the statement, that is, changing a true statement to a false statement and vice versa, using the word ‘not’ or ‘no’.
 
Example 1:
Change the true value of the following statements by using ‘no’ or ‘not’.
(a) 17 is a prime number.
(b) 39 is a multiple of 9.
 
Solution:
(a) 17 is not a prime number. (True to false)
(b) 39 not is a multiple of 9. (False to true)


2. A compound statement can be formed by combining two given statements using the word ‘and’.
 
Example 2:
Identify two statements from each of the following compound statements.
(a) All pentagons have 5 sides and 5 vertices.
(b) 33 = 27 and 43 = 64
 
Solution:
(a) All pentagons have 5 sides.
 All pentagons have 5 vertices.
(b) 33 = 27
  43 = 64


Example 3:
Form a compound statement from each of the following pairs of statements using the word ‘and’.
(a) 19 is a prime number.
  19 is an odd number.
(b) 15 – 5 = 10
  15 × 5 = 75

Solution:
(a) 19 is a prime number and an odd number. ← (Repeated words can be eliminated when combining two statements using ‘and’.)

(b) 15 – 5 = 10 and15 × 5 = 75.


3. A compound statement can also be formed by combining two given statements using the word ‘or’.
 
Example 4:
Form a compound statement from each of the following pairs of statements using the word ‘or’.
(a) 11 is an old number.
  11 is a prime number.
(b) 3 = 27 3 3 = 4 + 1

Solution:
(a) 11 is an old number or a prime number.
( b) 3 = 27 3 or 3 = 4 + 1


(B) Truth Values of Compound Statements using ‘And’
 
4. When two statements are combined using ‘and’, a true compound statement is obtained only if both statements are true.
 
5. If one or both statements are false, then the compound statement is false.
 
The truth table:
Let p = statement 1 and q = statement 2.
The truth values for ‘p’ and ‘q’ are as follows:

p
q
p and q (compound statement)
True
True
True
True
False
False
False
True
False
False
False
False
 
Example 5:
Determine the truth value of the following statements.
(a) 12 × (–3) = –36 and 15 – 7 = 8.
(b) 5 > 3 and –4 < –5.
(c) Hexagons have 5 sides and each of the interior angles is 90o.
 
Solution:
(a)
12 × (–3) = –36 ← (p is true)
15 – 7 = 8 ← (q is true)
Therefore 12 × (–3) = –36 and 15 – 7 = 8 is a true statement. (‘p and q’ is true)
 
(b)
5 > 3 ← (p is true)
–4 < –5 ← (q is false)
Therefore 5 > 3 and –4 < –5 is a false statement. (‘p and q’ is false)

(c)
Hexagons have 5 sides. ← (p is false)
Each of the interior angles of Hexagon is 90o. ← (qis false)
Therefore Hexagons have 5 sides and each of the interior angles is 90o is a false statement. (‘p and q’ is false)


(C) Truth Values of Compound Statements using ‘Or’
 
1. When two statements are combined using ‘or’, a false compound statement is obtained only if both statements are false.
 
2. f one or both statements are true, then the compound statement is true.
 
The truth table:
Let p = statement 1 and q= statement 2.
The truth values for ‘p’ or ‘q’ are as follows:
 
p
q
p or q (compound statement)
True
True
True
True
False
True
False
True
True
False
False
False
Example 6:
Determine the truth value of the following statements.
(a) 60 is divisible by 4 or 9.
(b) 53 = 25 or 43 = 64.
(c) 5 + 7 > 14 or √9 = 2.
 
Solution:
(a)
60 is divisible by 4  ← (p is true)
60 is divisible by 9  ← (q is false)
Therefore, 60 is divisible by 4 or 9 is a true statement. (‘p or q’ is true)
 
(b)
53 = 25  ← (p is false)
43 = 64  ← (q is true)
Therefore, 53 = 25 or 43 = 64 is a true statement. (‘por q’ is true)
 
(c)
5 + 7 > 14  ← (p is false)
√9 = 2  ← (qis false)
Therefore, 5 + 7 > 14 or √9 = 2 is a false statement. (‘p or q’ is false)

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