**Question 1**:

The diagram above shows the distance-time graph of a moving particle for 5 seconds. Find

**(a)**the distance travel by the particle from the time 2 second to 5 second.

**(b)**

**the speed of the particle for the first 2 seconds.**

Solution:Solution:

**(a)**

Distance travel by the particle from the time 2 second to 5 second

= 20 – 15

=

**5 m**

(b)

(b)

The speed of the particle for the first 2 seconds

= Gradient

$\begin{array}{l}=\frac{15-0}{2-0}\\ =7.5{\text{ms}}^{-1}\end{array}$**Question 2**:

The diagram above shows the distance-time graph of a moving car for 12 seconds. Find

**(a)**

**the value of v, if the average speed of the car for the first 6 seconds is 2 ms**

^{-1}.

**(b)**

**average speed of the car for the first 8 seconds.**

*Solution:***(a)**

$\begin{array}{l}{\text{Averagespeedofthecarforthefirst6secondsis2ms}}^{\text{-1}}\\ \frac{\text{Totaldistancetravelled}}{\text{Totaltimetaken}}=2\\ \frac{v}{6}=2\\ v=12\end{array}$

**(b)**

$\begin{array}{l}\text{Averagespeedofthecarforthefirst8seconds}\\ =\frac{15}{8}\\ =1.875\text{}m{s}^{-1}\end{array}$