Question 1:
Diagram 1 shows the stem-and-leaf plot for time taken by a group of students in a survey.
(a) State the number of students who took part in the survey. [1 mark]
(b) Determine the mode of distribution. [1 mark]
(c) Write one inference based on distribution of the time. [1 mark]
Solution:
(a)
Time of answering the Survey for each student
1st student = 15 minutes
2nd student = 18 minutes
3rd student = 32 minutes
.
.
.
.
.
12th student = 54 minutes
Number of students = 12
(b) Mode of distribution = 46
(c) Inference : Maximum time of answering the survey is 54 minutes
Diagram 1 shows the stem-and-leaf plot for time taken by a group of students in a survey.
(a) State the number of students who took part in the survey. [1 mark]
(b) Determine the mode of distribution. [1 mark]
(c) Write one inference based on distribution of the time. [1 mark]
Solution:
(a)
Time of answering the Survey for each student
1st student = 15 minutes
2nd student = 18 minutes
3rd student = 32 minutes
.
.
.
.
.
12th student = 54 minutes
Number of students = 12
(b) Mode of distribution = 46
(c) Inference : Maximum time of answering the survey is 54 minutes
Question 2:
(a) In the answer space, complete Table 1 for the equation y = 2x2 – 3 for -3 ⩽ x ⩽ 3. [1 mark]
(b) Hence, draw the graph of y = 2x2 – 3 for -3 ⩽ x ⩽ 3. [2 marks]
Solution:
(a)
y=2x2−3 When x=−2.5y=2(−2.5)2−3y=9.5y=2x2−3 When x=−2.5y=2(−2.5)2−3y=9.5
When x=−1.5y=2(−1.5)2−3y=1.5 When x=−1.5y=2(−1.5)2−3y=1.5
When x=1y=2(1)2−3y=−1 When x=1y=2(1)2−3y=−1
When x=1y=2(2)2−3y=5 When x=1y=2(2)2−3y=5
(b)
(a) In the answer space, complete Table 1 for the equation y = 2x2 – 3 for -3 ⩽ x ⩽ 3. [1 mark]
(b) Hence, draw the graph of y = 2x2 – 3 for -3 ⩽ x ⩽ 3. [2 marks]
Solution:
(a)
y=2x2−3 When x=−2.5y=2(−2.5)2−3y=9.5y=2x2−3 When x=−2.5y=2(−2.5)2−3y=9.5
When x=−1.5y=2(−1.5)2−3y=1.5 When x=−1.5y=2(−1.5)2−3y=1.5
When x=1y=2(1)2−3y=−1 When x=1y=2(1)2−3y=−1
When x=1y=2(2)2−3y=5 When x=1y=2(2)2−3y=5
(b)