7.5 probability II, SPM Practice (Long Questions)
Question 3:
A card is picked at random from box A and then a card is picked at random from box B.
By listing the sample of all possible outcomes of the event, find the probability that
(a) a card labelled M and a card with an even number are picked,
(b) a card labelled Q or a card with a number which is multiple of 2 are picked.
Solution:
Sample space, S
= {(M, 2), (M, 3), (M, 6), (Q, 2), (Q, 3), (Q, 6)}
n(S) = 6
(a)
{(M, 2), (M, 6)}
$P\left(M\text{and even number}\right)=\frac{2}{6}=\frac{1}{3}$
(b)
{(Q, 2), (Q, 3), (Q, 6), (M, 2), (M, 6)}
$P\left(Q\text{or multiple of 2}\right)=\frac{5}{6}$
Question 4:
Table below shows the names of participants from two secondary schools attending a public speaking training programme.
Boys 
Girls 

School A 
Karim 
Rosita
Sally
Linda 
School B 
Ahmad
Billy 
Nancy 
Two participants are required to give speeches at the end of the programme.
(a) A participant is chosen at random from School A and then another participant is chosen at random also from School A.
(i) List all the possible outcomes of the event in this sample space.
(ii)Hence, find the probability that a boy and a girl are chosen.
(b) A participant is chosen at random from the boys group and then another participant is chosen at random from the girls group.
(i) List all the possible outcomes of the event in this sample space.
(ii)Hence, find the probability that both participants chosen are from School B.
Solution:
(a)(i)
Sample space, S
= {(Karim, Rosita), (Karim, Sally), (Karim, Linda), (Rosita, Sally), (Rosita, Linda), (Sally, Linda)}
n(S) = 6
(a)(ii)
{(Karim, Rosita), (Karim, Sally), (Karim, Linda}
$P\left(\text{a boy and a girl}\right)=\frac{3}{6}=\frac{1}{2}$
(b)(i)
Sample space, S
= {(Karim, Rosita), (Karim, Sally), (Karim, Linda), (Karim, Nancy), (Ahmad, Rosita), (Ahmad, Sally), (Ahmad, Linda), (Ahmad, Nancy), (Billy, Rosita), (Billy, Sally), (Billy, Linda), (Billy, Nancy)}
n(S) = 12
(b)(ii)
{(Ahmad, Nancy), (Billy, Nancy)}
P (both participants from School B)
$\begin{array}{l}=\frac{2}{12}\\ =\frac{1}{6}\end{array}$