**Question 1:**

Diagram below shows two vertical poles on a horizontal plane.

*J*,*K*,*L*,*M*and*N*are five points on the poles such that*KL*=*MN*.Name the angle of elevation of point

*J*from point*M*.

*Solution:*Angle of elevation of point

*J*from point M=∠KMJ**Question 2:**

Diagram below shows two vertical poles

*JM*and*KL*, on a horizontal plane.The angle of depression of vertex

*K*from vertex*J*is 42^{o}.Calculate the angle of elevation of vertex

*K*from*M*.

*Solution:**NM*= 25 – 9.004 = 15.996 m

*KL*=

*NM*= 15.996 m

**Question 3:**

Diagram below shows a vertical pole

*KMN*on a horizontal plane. The angle of elevation of*M*from*L*is 20^{o}.

*Solution:*$\begin{array}{l}\mathrm{tan}{20}^{o}=\frac{KM}{KL}\\ 0.3640=\frac{KM}{15}\\ KM=5.4m\\ \text{Height of the pole =}9+5.4=14.4m\end{array}$