**Example 1**:

Given that the equation of a straight line is 4

*x*+ 6*y*– 3 = 0. What is the gradient of the line?

*Solution:*4

*x*+ 6*y*– 3 = 06

$\begin{array}{l}y=-\frac{4x}{6}+\frac{3}{6}\\ y=-\frac{2}{3}x+\frac{1}{2}\\ y=mx+c\\ gradient,\text{}m=-\frac{2}{3}\end{array}$
*y*= – 4*x*+ 3**Example 2**:

Given that the equation of a straight line is

*y*= – 7*x*+ 3. Find the*y*-intercept of the line?

Solution:Solution:

*y*= m

*x*+ c, c is y-intercept of the straight line.

Therefore for the straight line

*y*= – 7*x*+ 3,y-intercept is 3

**:**

Example 3

Example 3

Find the equation of the straight line MN if its gradient is equal to 3.

*Solution:*Given

*m*= 3Substitute

*m*= 3 and (-2, 5) into*y*= m*x*+ c.5 = 3 (-2) + c

5 = -6 + c

c = 11

Therefore the equation of the straight line

*MN*is*y*= 3*x*+ 11